integral of e^{1-x}x

解答

\int e^{1 - x} x d x

- e^{1 - x} x - e^{1 - x} + C

求解步骤

\int e^{1 - x} x d x

使用分布积分法

= - e^{1 - x} x - \int - e^{1 - x} d x

\int - e^{1 - x} d x = e^{1 - x}

= - e^{1 - x} x - e^{1 - x}

解答补常数

= - e^{1 - x} x - e^{1 - x} + C

\int (x - 1) x d x

\frac{\partial}{\partial x} (x^{2} sin (4 t))

\int \frac{x}{3 x + 4} d x

\frac{\partial}{\partial x} (2 x^{2} + y)

\frac{\partial}{\partial x} (\frac{1}{x})