What is the integral of 1/x sin(x) ?

The integral of 1/x sin(x) is \Si(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/x sin(x)

\int \frac{1}{x} sin (x) d x

Si (x) + C

Solution steps

\int \frac{1}{x} sin (x) d x

Simplify

\frac{1}{x} sin (x) : \frac{sin ( x )}{x}

= \int \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= Si (x)

Add a constant to the solution

= Si (x) + C

s l o p e y = 4 x - 3 x^{2}, (2, - 4)

\int \frac{sec ^{3} ( x )}{2} d x

x \to 0 lim (x^{2} + 2 x)

\int x^{- 0.5} d x

\frac{d}{d x} (0.0225 x e^{- 0.0467 x})