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人気のある微分積分 >

f^{''}(x)=e^x,f^'(0)=2,f(0)=5

解

f^{^{''}} (x) = e^{x}, f^{^{'}} (0) = 2, f (0) = 5

解

f (x) = e^{x} + x + 4

解答ステップ

f^{''} (x) = e^{x}

解く

f^{''} (x) = e^{x} : f^{'} (x) = e^{x} + c_{1}

解く

f^{'} (x) = e^{x} + c_{1} : f (x) = e^{x} + c_{1} x + c_{2}

初期条件を適用する:

f (x) = e^{x} + x + 4

f (x) = e^{x} + x + 4

グラフ

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