What is the derivative of (3sin(x)/(3+cos(x))) ?

The derivative of (3sin(x)/(3+cos(x))) is (3(1+3cos(x)))/((3+cos(x))^2)

What is the first derivative of (3sin(x)/(3+cos(x))) ?

The first derivative of (3sin(x)/(3+cos(x))) is (3(1+3cos(x)))/((3+cos(x))^2)

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\frac{d}{d x} (\frac{3 sin ( x )}{3 + cos ( x )})

\frac{3 ( 1 + 3 cos ( x ) )}{( 3 + cos ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 sin ( x )}{3 + cos ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{sin ( x )}{3 + cos ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d}{d x} ( sin ( x ) ) ( 3 + cos ( x ) ) - \frac{d}{d x} ( 3 + cos ( x ) ) sin ( x )}{( 3 + cos ( x ) ) ^{2}}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (3 + cos (x)) = - sin (x)

= 3 \cdot \frac{cos ( x ) ( 3 + cos ( x ) ) - ( - sin ( x ) ) sin ( x )}{( 3 + cos ( x ) ) ^{2}}

Simplify

3 \cdot \frac{cos ( x ) ( 3 + cos ( x ) ) - ( - sin ( x ) ) sin ( x )}{( 3 + cos ( x ) ) ^{2}} : \frac{3 ( 1 + 3 cos ( x ) )}{( 3 + cos ( x ) ) ^{2}}

= \frac{3 ( 1 + 3 cos ( x ) )}{( 3 + cos ( x ) ) ^{2}}

im pl i c i t \frac{d y}{d x}, e^{x y} + x^{2} - y^{2} = 12

n = 0 \sum \infty (\frac{1}{17})^{n}

x \to 0 lim (\frac{sin ( 5 x )}{6 x})

d er i v a t i v e f (x) = 3 sec (5 x)

d er i v a t i v e \frac{1 - 6 t}{5 + t}

What is the derivative of (3sin(x)/(3+cos(x))) ?
The derivative of (3sin(x)/(3+cos(x))) is (3(1+3cos(x)))/((3+cos(x))^2)
What is the first derivative of (3sin(x)/(3+cos(x))) ?
The first derivative of (3sin(x)/(3+cos(x))) is (3(1+3cos(x)))/((3+cos(x))^2)