ty^'-y=t^2e^{-t}

Lösung

t y^{^{'}} - y = t^{2} e^{- t}

y = - e^{- t} t + c_{1} t

Schritte zur Lösung

t y^{'} (t) - y = t^{2} e^{- t}

Solve linear ODE:

y = - e^{- t} t + c_{1} t

y = - e^{- t} t + c_{1} t

\int \frac{- 1 + x}{x ^{2}} d x

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