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人気のある微分積分 >

y^'+2/x y=-2xy^2

解

y^{^{'}} + \frac{2}{x} y = - 2 x y^{2}

解

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

解答ステップ

y^{'} (x) + \frac{2}{x} y = - 2 x y^{2}

ベルヌーイ ODE を解く:

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

y = \frac{1}{x ^{2} ( 2 ln ( x ) + c _{1} )}

グラフ

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