integral from 0 to 2 of ((x+2)/(x-4))

Lösung

\int_{0}^{2} (\frac{x + 2}{x - 4}) d x

- 6 ln (2) + 2

Dezimale

- 2.15888 \dots

Schritte zur Lösung

\int_{0}^{2} \frac{x + 2}{x - 4} d x

\frac{x + 2}{x - 4} = \frac{6}{x - 4} + 1

= \int_{0}^{2} \frac{6}{x - 4} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} \frac{6}{x - 4} d x + \int_{0}^{2} 1 d x

\int_{0}^{2} \frac{6}{x - 4} d x = - 6 ln (2)

\int_{0}^{2} 1 d x = 2

= - 6 ln (2) + 2

\int e^{7 θ} sin (8 θ) d θ

\int 4 e^{- 0.1 x} d x

a re a 3 sin (2 x), - 2 π, π

x \to 0 lim (\frac{( 3 arccos ( \frac{1}{2} + x ) - 3 arccos ( \frac{1}{2} ) )}{x})

\frac{d}{d x} (e^{- x^{7}})