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Frequently Asked Questions (FAQ)
What is the solution for y^'=(x-3)(y+1)^{2/3},y(0)=-1 ?
- The solution for y^'=(x-3)(y+1)^{2/3},y(0)=-1 is y=(x^6}{216}-(x^5)/(12)+\frac{x^4)/2-x^3-1