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Beliebt Rechnen >

25y^{''}-40y^'+16y=0,y(0)=2,y^'(0)=-3

Lösung

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (0) = 2, y^{^{'}} (0) = - 3

Lösung

y = 2 e^{\frac{4 t}{5}} - \frac{23 e ^{\frac{4 t}{5}} t}{5}

Schritte zur Lösung

25 y^{''} (t) - 40 y^{'} (t) + 16 y = 0

Solve linear ODE:

y = 2 e^{\frac{4 t}{5}} - \frac{23 e ^{\frac{4 t}{5}} t}{5}

y = 2 e^{\frac{4 t}{5}} - \frac{23 e ^{\frac{4 t}{5}} t}{5}

Graph

Beliebte Beispiele

integral of 5sin^3(x)cos^7(x)

\int 5 sin^{3} (x) cos^{7} (x) d x

integral from 1 to 2 of ln|x^2+1|

\int_{1}^{2} ln x^{2} + 1 d x

derivative of ln(4x-1)

\frac{d}{d x} (ln (4 x - 1))

integral from 4 to 5 of 1/(5x-1)

\int_{4}^{5} \frac{1}{5 x - 1} d x

xy^'+3y=(4e^{2x})/(x^2)

x y^{^{'}} + 3 y = \frac{4 e ^{2 x}}{x ^{2}}