What is the integral of cos(t)tan(t) ?

The integral of cos(t)tan(t) is -cos(t)+C

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integral of cos(t)tan(t)

\int cos (t) tan (t) d t

- cos (t) + C

Solution steps

\int cos (t) tan (t) d t

Express with sin, cos

= \int sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= - cos (t)

Add a constant to the solution

= - cos (t) + C

\frac{d}{d x} (x^{4} e^{4 x})

y^{^{'}} = y (x y^{4} - 1)

x^{2} \frac{d y}{d x} + x y = x^{3} + 1

\frac{d}{d x} (2 x + 6)

x \to \infty lim (\frac{x}{x ^{3} + 6})

What is the integral of cos(t)tan(t) ?
The integral of cos(t)tan(t) is -cos(t)+C