(dy)/(dx)+y^3x+2y=0

Lösung

\frac{d y}{d x} + y^{3} x + 2 y = 0

y = \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}, y = - \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}

Schritte zur Lösung

\frac{d y}{d x} + y^{3} x + 2 y = 0

Solve Bernoulli ODE:

y = \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}, y = - \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}

y = \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}, y = - \frac{2 2}{- 4 x - 1 + 8 c _{1} e ^{4 x}}

\int \frac{2}{x} + \frac{x}{2} d x

x \to \frac{π}{2} lim (\frac{csc ( 4 x )}{csc ( 2 x )})

t an g e n t f (x) = \frac{2 x - 1}{x + 5}, at x = 1

x \to - \infty lim (\frac{4 x ^{6}}{x ^{3} - 8})

θ \to \frac{π}{3} lim (\frac{tan ( θ )}{sin ^{2} ( θ )})