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受欢迎的微积分 >

tangent-5x^2+x-2

解答

切线

- 5 x^{2} + x - 2

解答

y = (- 10 a_{0} + 1) x + 5 a_{0}^{2} - 2

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, - 5 a_{0}^{2} + a_{0} - 2)

计算

y = - 5 x^{2} + x - 2

的斜率:

\frac{d y}{d x} = - 10 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 10 a_{0} + 1

找到斜率 m=

- 10 a_{0} + 1

且穿过

(a_{0}, - 5 a_{0}^{2} + a_{0} - 2)

的直线:

y = (- 10 a_{0} + 1) x + 5 a_{0}^{2} - 2

y = (- 10 a_{0} + 1) x + 5 a_{0}^{2} - 2

作图

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