y^'+ycos(x)=0

Lösung

y^{^{'}} + y cos (x) = 0

y = e^{- s i n (x) + c_{1}}

Schritte zur Lösung

y^{'} (x) + y cos (x) = 0

Solve separable ODE:

y = e^{- s i n (x) + c_{1}}

y = e^{- s i n (x) + c_{1}}

t a y l or x + 1

\int_{1}^{2} \frac{x ^{2} + 8}{3 x - x ^{2}} d x

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 1})

d er i v a t i v e \frac{7 + 2 x}{5 - 8 x}

\frac{\partial}{\partial x} (\frac{1}{tan ( x y )})