What is the derivative of 3cos(3x) ?

The derivative of 3cos(3x) is -9sin(3x)

What is the first derivative of 3cos(3x) ?

The first derivative of 3cos(3x) is -9sin(3x)

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\frac{d}{d x} (3 cos (3 x))

- 9 sin (3 x)

Solution steps

\frac{d}{d x} (3 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 3 (- sin (3 x) \cdot 3)

Simplify

= - 9 sin (3 x)

4 x^{\frac{5}{4}} + 10 x^{\frac{3}{2}} + 5 x

(1, - 2), (3, 1)

y^{^{''}} + 36 y = - 60 sin (6 t)

\frac{d y}{d t} = - 2 (1 + y^{2}) tan (2 t)

\frac{d}{d x} (\frac{( x - 7 )}{x + 7})

What is the derivative of 3cos(3x) ?
The derivative of 3cos(3x) is -9sin(3x)
What is the first derivative of 3cos(3x) ?
The first derivative of 3cos(3x) is -9sin(3x)