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Frequently Asked Questions (FAQ)
What is the tangent of y=(-2x)/((x^2+1)) ?
- The tangent of y=(-2x)/((x^2+1)) is y=-(2(-a_{0}^2+1))/((a_{0)^2+1)^2}x-(4a_{0}^3)/((a_{0)^2+1)^2}