What is the derivative of 25x^4+30x^3-11x^2-12x+4 ?

The derivative of 25x^4+30x^3-11x^2-12x+4 is 100x^3+90x^2-22x-12

What is the first derivative of 25x^4+30x^3-11x^2-12x+4 ?

The first derivative of 25x^4+30x^3-11x^2-12x+4 is 100x^3+90x^2-22x-12

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derivative of

25 x^{4} + 30 x^{3} - 11 x^{2} - 12 x + 4

100 x^{3} + 90 x^{2} - 22 x - 12

Solution steps

\frac{d}{d x} (25 x^{4} + 30 x^{3} - 11 x^{2} - 12 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (25 x^{4}) + \frac{d}{d x} (30 x^{3}) - \frac{d}{d x} (11 x^{2}) - \frac{d}{d x} (12 x) + \frac{d}{d x} (4)

\frac{d}{d x} (25 x^{4}) = 100 x^{3}

\frac{d}{d x} (30 x^{3}) = 90 x^{2}

\frac{d}{d x} (11 x^{2}) = 22 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (4) = 0

= 100 x^{3} + 90 x^{2} - 22 x - 12 + 0

Simplify

= 100 x^{3} + 90 x^{2} - 22 x - 12

(5 t + 3 y + 6) d t - d y = 0

y^{^{'}} - 3 y = 9 x

(- 3, - 1), (8, 2)

\frac{\partial}{\partial x} (x^{4} - x^{3} y + x y^{3} - y^{4})

x \to 0 lim (\frac{1}{x} + \frac{1}{∣ x ∣})

What is the derivative of 25x^4+30x^3-11x^2-12x+4 ?
The derivative of 25x^4+30x^3-11x^2-12x+4 is 100x^3+90x^2-22x-12
What is the first derivative of 25x^4+30x^3-11x^2-12x+4 ?
The first derivative of 25x^4+30x^3-11x^2-12x+4 is 100x^3+90x^2-22x-12