ln|x+2|=0

Lösung

ln ∣ x + 2 ∣ = 0

x = - 3, x = - 1

Schritte zur Lösung

ln ∣ x + 2 ∣ = 0

Wende die log Regel an

∣ x + 2 ∣ = 1

Löse

∣ x + 2 ∣ = 1 : x = - 3 or x = - 1

x = - 3, x = - 1

s im pl i f y \frac{a ^{- 4}}{a ^{- 2}}

f a c t or - 3 x^{3} - 9 x^{2} + 54 x

- 2 < 2 + 4 x < 14

3 x^{2} + 39 + 108 = 0

3 x + 2 \leq 1