2x^2-32x=0

解

2 x^{2} - 32 x = 0

x = 16, x = 0

解答ステップ

2 x^{2} - 32 x = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 32)^{2} - 4 \cdot 2 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 2}

解を分離する

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 2}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 2}

x = \frac{- ( - 32 ) + 32}{2 \cdot 2} : 16

x = \frac{- ( - 32 ) - 32}{2 \cdot 2} : 0

二次equationの解:

x = 16, x = 0