faktorisieren 4/5 y^2-64

Lösung

faktorisieren

\frac{4}{5} y^{2} - 64

(\frac{2 5 y}{5} + 8) (\frac{2 5 y}{5} - 8)

Schritte zur Lösung

\frac{4}{5} y^{2} - 64

Schreibe

\frac{4 y ^{2}}{5} - 64

um:

(\frac{4}{5} y)^{2} - 8^{2}

= (\frac{4}{5} y)^{2} - 8^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{4}{5} y)^{2} - 8^{2} = (\frac{4}{5} y + 8) (\frac{4}{5} y - 8)

= (\frac{4}{5} y + 8) (\frac{4}{5} y - 8)

Fasse zusammen

= (\frac{2 y}{5} + 8) (\frac{2 y}{5} - 8)

\frac{2 y}{5} = \frac{2 5 y}{5}

= (\frac{2 5 y}{5} + 8) (\frac{2 y}{5} - 8)

\frac{2 y}{5} = \frac{2 5 y}{5}

= (\frac{2 5 y}{5} + 8) (\frac{2 5 y}{5} - 8)

f a c t or c^{12} + 8 d^{6}

\frac{5}{6} x - 3 x + \frac{4}{3} = \frac{5}{3}

∣ 2 - x ∣ \leq \frac{3}{7}

s im pl i f y ln (0.9)

f a c t or 5 x^{2} + 17 x - 12