x^3-x<0

Lösung

x^{3} - x < 0

x < - 1 or 0 < x < 1

Intervall-Notation

(- \infty, - 1) \cup (0, 1)

Schritte zur Lösung

x^{3} - x < 0

Faktorisiere

x^{3} - x : x (x + 1) (x - 1)

x (x + 1) (x - 1) < 0

Identifiziere die Intervalle

x < - 1 or 0 < x < 1

3 + ∣ x - 3 ∣ > \frac{4}{7}

x^{2} + 4 x - 8 = 0

f a c t or 4 x^{4} - 17 x^{2} + 4

\frac{2 x}{3} - 2 = - 8

4 x \geq 36