|3-3/4 x|>3

Lösung

3 - \frac{3}{4} x > 3

x < 0 or x > 8

Intervall-Notation

(- \infty, 0) \cup (8, \infty)

Schritte zur Lösung

3 - \frac{3}{4} x > 3

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

3 - \frac{3}{4} x < - 3 or 3 - \frac{3}{4} x > 3

3 - \frac{3}{4} x < - 3 or 3 - \frac{3}{4} x > 3

x < 0 or x > 8

\frac{2 x - 1}{x + 2} \leq 4

x^{2} = 6 x - 2 x^{2}

\frac{3 x - 3}{9} \geq 1

∣ x ∣ - 10 = - 3

x^{2} + 3 x > 28