faktorisieren 15x^{2c+3}-25x^{c+1}

Lösung

faktorisieren

15 x^{2 c + 3} - 25 x^{c + 1}

5 x^{c + 1} (3 x^{c + 2} - 5)

Schritte zur Lösung

15 x^{2 c + 3} - 25 x^{c + 1}

Wende Exponentenregel an:

a^{b + c} = a^{b} \cdot a^{c}

x^{2 c + 3} = x^{2 c} x^{3}

= 15 x^{2 c} x^{3} - 25 x^{c + 1}

Wende Exponentenregel an:

a^{b + c} = a^{b} \cdot a^{c}

x^{c + 1} = x^{c} x

= 15 x^{2 c} x^{3} - 25 x^{c} x

Klammere gleiche Terme aus

5 x^{c} x : 5 x^{c} x (3 x^{c} x^{2} - 5)

= 5 x^{c} x (3 x^{c} x^{2} - 5)

Vereinfache

5 x^{c} x (3 x^{c} x^{2} - 5) : 5 x^{c + 1} (3 x^{c + 2} - 5)

= 5 x^{c + 1} (3 x^{c + 2} - 5)

f a c t or v^{2} - 7 v + 10

- 3 (- 7 x + 4) - 4 x = - 1.5 (- 5 x + 8.6) + 2 x

(3 x + 2) (- \frac{1}{2}) = - 5 x (\frac{1}{2}) - x + \frac{2}{3}

\frac{1}{3} x - 4 = - 8

\frac{5}{9} (F - 32) = - 62.1