vereinfachen (64s^{3/7})^{1/6}

Lösung

vereinfachen

(64 s^{\frac{3}{7}})^{\frac{1}{6}}

2 s^{\frac{1}{14}}

Schritte zur Lösung

(64 s^{\frac{3}{7}})^{\frac{1}{6}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(64 s^{\frac{3}{7}})^{\frac{1}{6}} = 6 4^{\frac{1}{6}} (s^{\frac{3}{7}})^{\frac{1}{6}}

= 6 4^{\frac{1}{6}} (s^{\frac{3}{7}})^{\frac{1}{6}}

6 4^{\frac{1}{6}} = 2

= 2 (s^{\frac{3}{7}})^{\frac{1}{6}}

Wende Exponentenregel an:

(a^{b})^{c} = a^{b c},

angenommen

a \geq 0

(s^{\frac{3}{7}})^{\frac{1}{6}} = s^{\frac{3}{7} \cdot \frac{1}{6}}

= 2 s^{\frac{3}{7} \cdot \frac{1}{6}}

\frac{3}{7} \cdot \frac{1}{6} = \frac{1}{14}

= 2 s^{\frac{1}{14}}

2 (5 x + 1) = 22

3 x - 1 \geq x - 2 \geq - 5

s im pl i f y lo g_{3} (3)

s im pl i f y \frac{x}{\frac{1}{y}}

s im pl i f y ln (12) - ln (4)