p^2-2p-3=0

解答

p^{2} - 2 p - 3 = 0

p = 3, p = - 1

求解步骤

p^{2} - 2 p - 3 = 0

使用求根公式求解

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

p_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

将解分隔开

p_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

p = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

p = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

二次方程组的解是:

p = 3, p = - 1

10 \leq r

(x + 1)^{2} + (- 2 x + 8)^{2} = 40

f a c t or 625 m^{5} - 256 m n^{4}

2 4^{2} + 7^{2} = c^{2}

s im pl i f y (1 - 82) (1 + 82)