4n^2+4n-8=0

解

4 n^{2} + 4 n - 8 = 0

n = 1, n = - 2

解答ステップ

4 n^{2} + 4 n - 8 = 0

解くとthe二次式

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 8 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 8) = 12

n_{1, 2} = \frac{- 4 \pm 12}{2 \cdot 4}

解を分離する

n_{1} = \frac{- 4 + 12}{2 \cdot 4}, n_{2} = \frac{- 4 - 12}{2 \cdot 4}

n = \frac{- 4 + 12}{2 \cdot 4} : 1

n = \frac{- 4 - 12}{2 \cdot 4} : - 2

二次equationの解:

n = 1, n = - 2