What is the answer to |x+1|+|x-2|=3 ?

The answer to |x+1|+|x-2|=3 is -1<= x<= 2

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|x+1|+|x-2|=3

∣ x + 1 ∣ + ∣ x - 2 ∣ = 3

- 1 \leq x \leq 2

Solution steps

∣ x + 1 ∣ + ∣ x - 2 ∣ = 3

Find positive and negative intervals

x < - 1, - 1 \leq x < 2, x \geq 2

Solve the inequality for each interval

No Solution or - 1 \leq x < 2 or x = 2

Merge Overlapping Intervals

- 1 \leq x \leq 2

\frac{3}{5} (- \frac{60}{3})

3 x - 4 - 3 (x + 5) = - 6 (x + 1)

\frac{28 !}{( 28 - 6 ) ! 6 !}

29 = - 8 y - 7 + 5 y

x^{2} - 3 x - 30 = 0