What are the solutions to the equation -98y^2+2=0 ?

The solutions to the equation -98y^2+2=0 are y= 1/7 ,y=-1/7

Find the zeros of -98y^2+2=0

The zeros of -98y^2+2=0 are y= 1/7 ,y=-1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 98 y^{2} + 2 = 0

y = \frac{1}{7}, y = - \frac{1}{7}

Decimal Notation

y = 0.14285 \dots, y = - 0.14285 \dots

Solution steps

- 98 y^{2} + 2 = 0

Move

2

to the right side

- 98 y^{2} = - 2

Divide both sides by

- 98

y^{2} = \frac{1}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{1}{49}, y = - \frac{1}{49}

\frac{1}{49} = \frac{1}{7}

- \frac{1}{49} = - \frac{1}{7}

y = \frac{1}{7}, y = - \frac{1}{7}

2600

(\frac{2 x y ^{2}}{z} + 5 x z^{2} + 2 x yz) (3 x y^{3} - \frac{2}{z})

14 x^{2} - 53 x + 14

14 - 6 (a + 2) = 9 + a

25 a^{2} - 16 b^{2}

What are the solutions to the equation -98y^2+2=0 ?
The solutions to the equation -98y^2+2=0 are y= 1/7 ,y=-1/7
Find the zeros of -98y^2+2=0
The zeros of -98y^2+2=0 are y= 1/7 ,y=-1/7