What are the solutions to the equation 2x^2+3x-10=0 ?

The solutions to the equation 2x^2+3x-10=0 are x=(-3+sqrt(89))/4 ,x=(-3-sqrt(89))/4

Find the zeros of 2x^2+3x-10=0

The zeros of 2x^2+3x-10=0 are x=(-3+sqrt(89))/4 ,x=(-3-sqrt(89))/4

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2 x^{2} + 3 x - 10 = 0

x = \frac{- 3 + 89}{4}, x = \frac{- 3 - 89}{4}

Decimal Notation

x = 1.60849 \dots, x = - 3.10849 \dots

Solution steps

2 x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 10) = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 \cdot 2}, x_{2} = \frac{- 3 - 89}{2 \cdot 2}

x = \frac{- 3 + 89}{2 \cdot 2} : \frac{- 3 + 89}{4}

x = \frac{- 3 - 89}{2 \cdot 2} : \frac{- 3 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 89}{4}, x = \frac{- 3 - 89}{4}

3 x^{2} - 9 x - 12

x^{3} - 2 x^{2} - 8 x

\frac{2}{27} - \frac{1}{2}

9 x y - 3 x^{3} y^{2}

3 x^{2} - 20 = 7

What are the solutions to the equation 2x^2+3x-10=0 ?
The solutions to the equation 2x^2+3x-10=0 are x=(-3+sqrt(89))/4 ,x=(-3-sqrt(89))/4
Find the zeros of 2x^2+3x-10=0
The zeros of 2x^2+3x-10=0 are x=(-3+sqrt(89))/4 ,x=(-3-sqrt(89))/4