What are the solutions to the equation k^2=225 ?

The solutions to the equation k^2=225 are k=15,k=-15

Find the zeros of k^2=225

The zeros of k^2=225 are k=15,k=-15

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k^{2} = 225

k = 15, k = - 15

Solution steps

k^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 225, k = - 225

225 = 15

- 225 = - 15

k = 15, k = - 15

- 0.5

2 x \geq 3 x^{2} + 16

x^{2} + 14 x + 33

2 x^{2} - 3 x - 27 = 0

\frac{3}{4} x + 13 = 88

What are the solutions to the equation k^2=225 ?
The solutions to the equation k^2=225 are k=15,k=-15
Find the zeros of k^2=225
The zeros of k^2=225 are k=15,k=-15