What are the solutions to the equation x^2+0.1x+1=0 ?

The solutions to the equation x^2+0.1x+1=0 are x=-1/20+i(sqrt(399))/(20),x=-1/20-i(sqrt(399))/(20)

Find the zeros of x^2+0.1x+1=0

The zeros of x^2+0.1x+1=0 are x=-1/20+i(sqrt(399))/(20),x=-1/20-i(sqrt(399))/(20)

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x^{2} + 0.1 x + 1 = 0

x = - \frac{1}{20} + i \frac{399}{20}, x = - \frac{1}{20} - i \frac{399}{20}

Solution steps

x^{2} + 0.1 x + 1 = 0

Multiply both sides by

10

10 x^{2} + x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

1^{2} - 4 \cdot 10 \cdot 10 : 399 i

x_{1, 2} = \frac{- 1 \pm 399 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 399 i}{2 \cdot 10}, x_{2} = \frac{- 1 - 399 i}{2 \cdot 10}

x = \frac{- 1 + 399 i}{2 \cdot 10} : - \frac{1}{20} + i \frac{399}{20}

x = \frac{- 1 - 399 i}{2 \cdot 10} : - \frac{1}{20} - i \frac{399}{20}

The solutions to the quadratic equation are:

x = - \frac{1}{20} + i \frac{399}{20}, x = - \frac{1}{20} - i \frac{399}{20}

(1 - i 2)^{2}

(0 - 2)^{2} + (y + 7)^{2} = 9

9 y^{2} - 30 y + 25

6 x^{3} - 11 x^{2} - 10 x

(x y)^{3}

What are the solutions to the equation x^2+0.1x+1=0 ?
The solutions to the equation x^2+0.1x+1=0 are x=-1/20+i(sqrt(399))/(20),x=-1/20-i(sqrt(399))/(20)
Find the zeros of x^2+0.1x+1=0
The zeros of x^2+0.1x+1=0 are x=-1/20+i(sqrt(399))/(20),x=-1/20-i(sqrt(399))/(20)