What are the solutions to the equation 40x^2+17x-5=0 ?

The solutions to the equation 40x^2+17x-5=0 are x= 1/5 ,x=-5/8

Find the zeros of 40x^2+17x-5=0

The zeros of 40x^2+17x-5=0 are x= 1/5 ,x=-5/8

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40 x^{2} + 17 x - 5 = 0

x = \frac{1}{5}, x = - \frac{5}{8}

Decimal Notation

x = 0.2, x = - 0.625

Solution steps

40 x^{2} + 17 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 40 ( - 5 )}{2 \cdot 40}

1 7^{2} - 4 \cdot 40 (- 5) = 33

x_{1, 2} = \frac{- 17 \pm 33}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- 17 + 33}{2 \cdot 40}, x_{2} = \frac{- 17 - 33}{2 \cdot 40}

x = \frac{- 17 + 33}{2 \cdot 40} : \frac{1}{5}

x = \frac{- 17 - 33}{2 \cdot 40} : - \frac{5}{8}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{5}{8}

(x + 4)^{2}

\frac{- 9 n ^{8}}{27 n ^{10}}

4 \cdot 0.5

3 (3 + x) = 15 + x

4 x - 5 > 7 and - 2 x + 1 \leq 5

What are the solutions to the equation 40x^2+17x-5=0 ?
The solutions to the equation 40x^2+17x-5=0 are x= 1/5 ,x=-5/8
Find the zeros of 40x^2+17x-5=0
The zeros of 40x^2+17x-5=0 are x= 1/5 ,x=-5/8