What are the solutions to the equation 240=w(2w-4) ?

The solutions to the equation 240=w(2w-4) are w=12,w=-10

Find the zeros of 240=w(2w-4)

The zeros of 240=w(2w-4) are w=12,w=-10

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240 = w (2 w - 4)

w = 12, w = - 10

Solution steps

240 = w (2 w - 4)

Expand

w (2 w - 4) : 2 w^{2} - 4 w

240 = 2 w^{2} - 4 w

Switch sides

2 w^{2} - 4 w = 240

Move

240

to the left side

2 w^{2} - 4 w - 240 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 240 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 240) = 44

w_{1, 2} = \frac{- ( - 4 ) \pm 44}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 44}{2 \cdot 2}, w_{2} = \frac{- ( - 4 ) - 44}{2 \cdot 2}

w = \frac{- ( - 4 ) + 44}{2 \cdot 2} : 12

w = \frac{- ( - 4 ) - 44}{2 \cdot 2} : - 10

The solutions to the quadratic equation are:

w = 12, w = - 10

\frac{1}{4} n^{2} + 3 = 4

7^{2} + b^{2} = 2 5^{2}

4 x + 2 + x^{2} = 0

2 x^{3} - x^{4} \leq 0

lo g_{\frac{1}{4}} (\frac{1}{16})

What are the solutions to the equation 240=w(2w-4) ?
The solutions to the equation 240=w(2w-4) are w=12,w=-10
Find the zeros of 240=w(2w-4)
The zeros of 240=w(2w-4) are w=12,w=-10