What is ((3xy)^2(2x^4y^3))/(6x^8y) ?

The solution to ((3xy)^2(2x^4y^3))/(6x^8y) is (3y^4)/(x^2)

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simplify ((3xy)^2(2x^4y^3))/(6x^8y)

simplify

\frac{( 3 x y ) ^{2} ( 2 x ^{4} y ^{3} )}{6 x ^{8} y}

\frac{3 y ^{4}}{x ^{2}}

Solution steps

\frac{( 3 x y ) ^{2} ( 2 x ^{4} y ^{3} )}{6 x ^{8} y}

Factor the number:

6 = 2 \cdot 3

= \frac{( 3 x y ) ^{2} \cdot 2 x ^{4} y ^{3}}{2 \cdot 3 x ^{8} y}

Cancel the common factor:

2

= \frac{( 3 x y ) ^{2} x ^{4} y ^{3}}{3 x ^{8} y}

Simplify

\frac{y ^{3}}{y} : y^{2}

= \frac{( 3 x y ) ^{2} x ^{4} y ^{2}}{3 x ^{8}}

Simplify

\frac{x ^{4}}{x ^{8}} : \frac{1}{x ^{4}}

= \frac{( 3 x y ) ^{2} y ^{2}}{3 x ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(3 x y)^{2} = 3^{2} x^{2} y^{2}

= \frac{3 ^{2} x ^{2} y ^{2} y ^{2}}{3 x ^{4}}

\frac{3 ^{2}}{3} = 3

= \frac{3 x ^{2} y ^{2} y ^{2}}{x ^{4}}

Simplify

\frac{x ^{2}}{x ^{4}} : \frac{1}{x ^{2}}

= \frac{3 y ^{2} y ^{2}}{x ^{2}}

Simplify

y^{2} y^{2} : y^{4}

= \frac{3 y ^{4}}{x ^{2}}

\frac{12}{5 y ^{2}} - \frac{2}{5 yz}

2 (- 27)^{\frac{8}{3}}

4 d - 1 > - 3

1 - [\frac{- 6}{100} e^{- 5} + 0.01]

\frac{\frac{2}{2}}{- \frac{2}{2}}

What is ((3xy)^2(2x^4y^3))/(6x^8y) ?
The solution to ((3xy)^2(2x^4y^3))/(6x^8y) is (3y^4)/(x^2)