What are the solutions to the equation x^2-45=4x ?

The solutions to the equation x^2-45=4x are x=9,x=-5

Find the zeros of x^2-45=4x

The zeros of x^2-45=4x are x=9,x=-5

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x^{2} - 45 = 4 x

x = 9, x = - 5

Solution steps

x^{2} - 45 = 4 x

Move

4 x

to the left side

x^{2} - 45 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 1}

x = \frac{- ( - 4 ) + 14}{2 \cdot 1} : 9

x = \frac{- ( - 4 ) - 14}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 9, x = - 5

47 m^{2} + 88 m + 39 = 0

(\frac{1}{3})^{4}

9 v + 2 \geq 6 v + 8 or - 10 - 8 v > 3 v - 10

\frac{\frac{1}{2}}{\frac{1}{2}}

- 3 = a - 11

What are the solutions to the equation x^2-45=4x ?
The solutions to the equation x^2-45=4x are x=9,x=-5
Find the zeros of x^2-45=4x
The zeros of x^2-45=4x are x=9,x=-5