What are the solutions to the equation x(3x+4)=5 ?

The solutions to the equation x(3x+4)=5 are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3

Find the zeros of x(3x+4)=5

The zeros of x(3x+4)=5 are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (3 x + 4) = 5

x = \frac{- 2 + 19}{3}, x = - \frac{2 + 19}{3}

Decimal Notation

x = 0.78629 \dots, x = - 2.11963 \dots

Solution steps

x (3 x + 4) = 5

Expand

x (3 x + 4) : 3 x^{2} + 4 x

3 x^{2} + 4 x = 5

Move

5

to the left side

3 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 5) = 219

x_{1, 2} = \frac{- 4 \pm 2 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 19}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 19}{2 \cdot 3}

x = \frac{- 4 + 2 19}{2 \cdot 3} : \frac{- 2 + 19}{3}

x = \frac{- 4 - 2 19}{2 \cdot 3} : - \frac{2 + 19}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 19}{3}, x = - \frac{2 + 19}{3}

21 x^{2} - 16 x - 16

- 1 = 5 + \frac{x}{6}

2 - \frac{9}{2}

2 (w + 2) - 3 w \geq 1

6 (3 p - 2) = 20

What are the solutions to the equation x(3x+4)=5 ?
The solutions to the equation x(3x+4)=5 are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3
Find the zeros of x(3x+4)=5
The zeros of x(3x+4)=5 are x=(-2+sqrt(19))/3 ,x=-(2+sqrt(19))/3