What are the solutions to the equation 6x^2-9x+4=0 ?

The solutions to the equation 6x^2-9x+4=0 are x= 3/4+i(sqrt(15))/(12),x= 3/4-i(sqrt(15))/(12)

Find the zeros of 6x^2-9x+4=0

The zeros of 6x^2-9x+4=0 are x= 3/4+i(sqrt(15))/(12),x= 3/4-i(sqrt(15))/(12)

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6 x^{2} - 9 x + 4 = 0

x = \frac{3}{4} + i \frac{15}{12}, x = \frac{3}{4} - i \frac{15}{12}

Solution steps

6 x^{2} - 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

Simplify

(- 9)^{2} - 4 \cdot 6 \cdot 4 : 15 i

x_{1, 2} = \frac{- ( - 9 ) \pm 15 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15 i}{2 \cdot 6}, x_{2} = \frac{- ( - 9 ) - 15 i}{2 \cdot 6}

x = \frac{- ( - 9 ) + 15 i}{2 \cdot 6} : \frac{3}{4} + i \frac{15}{12}

x = \frac{- ( - 9 ) - 15 i}{2 \cdot 6} : \frac{3}{4} - i \frac{15}{12}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{15}{12}, x = \frac{3}{4} - i \frac{15}{12}

x^{2} - 3 x + \frac{9}{4}

(3 x - 6) (- x + 3) = 0

x^{2} + 14 x - 21 = 10 x

∣ 2 - x ∣ = 6

r^{3} + 125

What are the solutions to the equation 6x^2-9x+4=0 ?
The solutions to the equation 6x^2-9x+4=0 are x= 3/4+i(sqrt(15))/(12),x= 3/4-i(sqrt(15))/(12)
Find the zeros of 6x^2-9x+4=0
The zeros of 6x^2-9x+4=0 are x= 3/4+i(sqrt(15))/(12),x= 3/4-i(sqrt(15))/(12)