What is (2x^4y^3z^2)/(10x^{-2)y^{-1}z} ?

The solution to (2x^4y^3z^2)/(10x^{-2)y^{-1}z} is (x^6y^4z)/5

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simplify (2x^4y^3z^2)/(10x^{-2)y^{-1}z}

simplify

\frac{2 x ^{4} y ^{3} z ^{2}}{10 x ^{- 2} y ^{- 1} z}

\frac{x ^{6} y ^{4} z}{5}

Solution steps

\frac{2 x ^{4} y ^{3} z ^{2}}{10 x ^{- 2} y ^{- 1} z}

Factor the number:

10 = 2 \cdot 5

= \frac{2 x ^{4} y ^{3} z ^{2}}{2 \cdot 5 x ^{- 2} y ^{- 1} z}

Cancel the common factor:

2

= \frac{x ^{4} y ^{3} z ^{2}}{5 x ^{- 2} y ^{- 1} z}

Simplify

\frac{x ^{4}}{x ^{- 2}} : x^{6}

= \frac{x ^{6} y ^{3} z ^{2}}{5 y ^{- 1} z}

Simplify

\frac{y ^{3}}{y ^{- 1}} : y^{4}

= \frac{x ^{6} y ^{4} z ^{2}}{5 z}

Simplify

\frac{z ^{2}}{z} : z

= \frac{x ^{6} y ^{4} z}{5}

- 7 h + 2 (- 4 h + 5) > - 4 h + 1 + 10

\frac{5}{2 x - 1} \geq \frac{1}{x - 2}

8 = x^{2} - 4

4 x^{4} + 7 x^{2} - 2 = 0

- 4 (2 x - 6) = 10 x

What is (2x^4y^3z^2)/(10x^{-2)y^{-1}z} ?
The solution to (2x^4y^3z^2)/(10x^{-2)y^{-1}z} is (x^6y^4z)/5