What are the solutions to the equation 5v^2+20v+10=4v ?

The solutions to the equation 5v^2+20v+10=4v are v=(-8+sqrt(14))/5 ,v=-(8+sqrt(14))/5

Find the zeros of 5v^2+20v+10=4v

The zeros of 5v^2+20v+10=4v are v=(-8+sqrt(14))/5 ,v=-(8+sqrt(14))/5

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5 v^{2} + 20 v + 10 = 4 v

v = \frac{- 8 + 14}{5}, v = - \frac{8 + 14}{5}

Decimal Notation

v = - 0.85166 \dots, v = - 2.34833 \dots

Solution steps

5 v^{2} + 20 v + 10 = 4 v

Move

4 v

to the left side

5 v^{2} + 16 v + 10 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

1 6^{2} - 4 \cdot 5 \cdot 10 = 214

v_{1, 2} = \frac{- 16 \pm 2 14}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 16 + 2 14}{2 \cdot 5}, v_{2} = \frac{- 16 - 2 14}{2 \cdot 5}

v = \frac{- 16 + 2 14}{2 \cdot 5} : \frac{- 8 + 14}{5}

v = \frac{- 16 - 2 14}{2 \cdot 5} : - \frac{8 + 14}{5}

The solutions to the quadratic equation are:

v = \frac{- 8 + 14}{5}, v = - \frac{8 + 14}{5}

\frac{1}{5} x + \frac{1}{2} = - 4 (\frac{3}{4} x - 4)

\frac{3}{4} x = 2

(x - 2)^{2} + (x + 1)^{2} = 3

\frac{- 2 - 4 i}{7 i}

16 x^{2} + 7 = 12

What are the solutions to the equation 5v^2+20v+10=4v ?
The solutions to the equation 5v^2+20v+10=4v are v=(-8+sqrt(14))/5 ,v=-(8+sqrt(14))/5
Find the zeros of 5v^2+20v+10=4v
The zeros of 5v^2+20v+10=4v are v=(-8+sqrt(14))/5 ,v=-(8+sqrt(14))/5