What are the solutions to the equation 2x^2+3x=42-2x ?

The solutions to the equation 2x^2+3x=42-2x are x= 7/2 ,x=-6

Find the zeros of 2x^2+3x=42-2x

The zeros of 2x^2+3x=42-2x are x= 7/2 ,x=-6

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2 x^{2} + 3 x = 42 - 2 x

x = \frac{7}{2}, x = - 6

Decimal Notation

x = 3.5, x = - 6

Solution steps

2 x^{2} + 3 x = 42 - 2 x

Move

2 x

to the left side

2 x^{2} + 5 x = 42

Move

42

to the left side

2 x^{2} + 5 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 42 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 42) = 19

x_{1, 2} = \frac{- 5 \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 19}{2 \cdot 2}, x_{2} = \frac{- 5 - 19}{2 \cdot 2}

x = \frac{- 5 + 19}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 5 - 19}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 6

2 x^{3} - 3 x^{2} - 2 x + 3

2 x^{2} - 3 x = 2 x - 2

v^{2} - 5 v + 4

(t - 4)^{2} = (t + 4)^{2} + 16

265

What are the solutions to the equation 2x^2+3x=42-2x ?
The solutions to the equation 2x^2+3x=42-2x are x= 7/2 ,x=-6
Find the zeros of 2x^2+3x=42-2x
The zeros of 2x^2+3x=42-2x are x= 7/2 ,x=-6