化简 (6i)/(9-9i)

解答

化简

\frac{6 i}{9 - 9 i}

- \frac{1}{3} + \frac{1}{3} i

求解步骤

\frac{6 i}{9 - 9 i}

乘以共轭根式

\frac{9 + 9 i}{9 + 9 i}

= \frac{6 i ( 9 + 9 i )}{( 9 - 9 i ) ( 9 + 9 i )}

化简

\frac{6 i ( 9 + 9 i )}{( 9 - 9 i ) ( 9 + 9 i )} : \frac{54 i - 54}{162}

= \frac{54 i - 54}{162}

Rewrite in standard complex form:

- \frac{1}{3} + \frac{1}{3} i

= - \frac{1}{3} + \frac{1}{3} i

(2 x + 1)^{2} = 12

f a c t or 4 v^{2} - 64

s im pl i f y (\frac{3 x}{y})^{- 3}

∣ 3 x - 4 ∣ \geq 2

6 (2 m - 3) - 3 m = 2 m - 18 + m