What are the solutions to the equation (z+2)^2+20=0 ?

The solutions to the equation (z+2)^2+20=0 are z=2sqrt(5)i-2,z=-2sqrt(5)i-2

Find the zeros of (z+2)^2+20=0

The zeros of (z+2)^2+20=0 are z=2sqrt(5)i-2,z=-2sqrt(5)i-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(z + 2)^{2} + 20 = 0

z = 25 i - 2, z = - 25 i - 2

Solution steps

(z + 2)^{2} + 20 = 0

Move

20

to the right side

(z + 2)^{2} = - 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 2 = - 20 : z = 25 i - 2

Solve

z + 2 = - - 20 : z = - 25 i - 2

The solutions to the quadratic equation are:

z = 25 i - 2, z = - 25 i - 2

(x^{\frac{6}{5}})^{\frac{5}{3}}

4 x + 14

\frac{2 x - 1}{x + 5} > 2

a - 5 < 5

\frac{5}{3} + \frac{4}{8} + \frac{3}{5}

What are the solutions to the equation (z+2)^2+20=0 ?
The solutions to the equation (z+2)^2+20=0 are z=2sqrt(5)i-2,z=-2sqrt(5)i-2
Find the zeros of (z+2)^2+20=0
The zeros of (z+2)^2+20=0 are z=2sqrt(5)i-2,z=-2sqrt(5)i-2