What are the solutions to the equation -3x^2+8=0 ?

The solutions to the equation -3x^2+8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

Find the zeros of -3x^2+8=0

The zeros of -3x^2+8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

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- 3 x^{2} + 8 = 0

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 1.63299 \dots, x = - 1.63299 \dots

Solution steps

- 3 x^{2} + 8 = 0

Move

8

to the right side

- 3 x^{2} = - 8

Divide both sides by

- 3

x^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{3}, x = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

3 x + 5 < 17

6 + 9 v = 2 (v - 11)

9 x^{3} - 27 x^{2} - x + 3

9 y^{2} + 18 y - 12 = 6 y

∣ x + 2 ∣ = 10

What are the solutions to the equation -3x^2+8=0 ?
The solutions to the equation -3x^2+8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))
Find the zeros of -3x^2+8=0
The zeros of -3x^2+8=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))