What are the solutions to the equation x^2+8x+15=0 ?

The solutions to the equation x^2+8x+15=0 are x=-3,x=-5

Find the zeros of x^2+8x+15=0

The zeros of x^2+8x+15=0 are x=-3,x=-5

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x^{2} + 8 x + 15 = 0

x = - 3, x = - 5

Solution steps

x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 2}{2 \cdot 1}

x = \frac{- 8 + 2}{2 \cdot 1} : - 3

x = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

(m - 3) (3 m + 4) = 5 (m + 1) + 8

- 2 294 m^{16} n^{7}

\frac{3 x y ^{2}}{5 x y ^{3}}

x^{3} + x^{2} - 14 x - 24

∣ x ∣ > \frac{1}{6}

What are the solutions to the equation x^2+8x+15=0 ?
The solutions to the equation x^2+8x+15=0 are x=-3,x=-5
Find the zeros of x^2+8x+15=0
The zeros of x^2+8x+15=0 are x=-3,x=-5