(x-7)(x+5)<0

Lösung

(x - 7) (x + 5) < 0

- 5 < x < 7

Intervall-Notation

(- 5, 7)

Schritte zur Lösung

(x - 7) (x + 5) < 0

Identifiziere die Intervalle

- 5 < x < 7

x^{2} = 4 x + 12

2 x - \frac{x}{2} + \frac{x + 1}{4} = 6 x

x^{2} + 3 x - 130 = 0

- 1 \leq \frac{2 x - 3}{2} < 4

f a c t or - 21 x - 6 x^{2}