What are the solutions to the equation 4x^2+2x-2=1 ?

The solutions to the equation 4x^2+2x-2=1 are x=(-1+sqrt(13))/4 ,x=-(1+sqrt(13))/4

Find the zeros of 4x^2+2x-2=1

The zeros of 4x^2+2x-2=1 are x=(-1+sqrt(13))/4 ,x=-(1+sqrt(13))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 2 x - 2 = 1

x = \frac{- 1 + 13}{4}, x = - \frac{1 + 13}{4}

Decimal Notation

x = 0.65138 \dots, x = - 1.15138 \dots

Solution steps

4 x^{2} + 2 x - 2 = 1

Move

1

to the left side

4 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 3) = 213

x_{1, 2} = \frac{- 2 \pm 2 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 13}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 13}{2 \cdot 4}

x = \frac{- 2 + 2 13}{2 \cdot 4} : \frac{- 1 + 13}{4}

x = \frac{- 2 - 2 13}{2 \cdot 4} : - \frac{1 + 13}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{4}, x = - \frac{1 + 13}{4}

x^{4} + 4 x^{2} - 12

x y + 4 y - 8 x - 32

- (4)^{- 2}

- 4 (2 x - 4) - 2 x - 2 = - 36

f = - \frac{1}{3} + 4

What are the solutions to the equation 4x^2+2x-2=1 ?
The solutions to the equation 4x^2+2x-2=1 are x=(-1+sqrt(13))/4 ,x=-(1+sqrt(13))/4
Find the zeros of 4x^2+2x-2=1
The zeros of 4x^2+2x-2=1 are x=(-1+sqrt(13))/4 ,x=-(1+sqrt(13))/4