What are the solutions to the equation -2x^2-7x-5=0 ?

The solutions to the equation -2x^2-7x-5=0 are x=-5/2 ,x=-1

Find the zeros of -2x^2-7x-5=0

The zeros of -2x^2-7x-5=0 are x=-5/2 ,x=-1

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- 2 x^{2} - 7 x - 5 = 0

x = - \frac{5}{2}, x = - 1

Decimal Notation

x = - 2.5, x = - 1

Solution steps

- 2 x^{2} - 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

(- 7)^{2} - 4 (- 2) (- 5) = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 ( - 2 )}, x_{2} = \frac{- ( - 7 ) - 3}{2 ( - 2 )}

x = \frac{- ( - 7 ) + 3}{2 ( - 2 )} : - \frac{5}{2}

x = \frac{- ( - 7 ) - 3}{2 ( - 2 )} : - 1

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = - 1

32 a^{2} + 24 b^{2}

x^{2} + \frac{3}{4} = 0

\frac{3}{8} (2 x - 3) - \frac{4}{3} (x - 2) = \frac{2}{3}

2 x^{2} + x - 1 = 2 x + 1

\frac{5 !}{1 ! ( 5 - 1 ) !}

What are the solutions to the equation -2x^2-7x-5=0 ?
The solutions to the equation -2x^2-7x-5=0 are x=-5/2 ,x=-1
Find the zeros of -2x^2-7x-5=0
The zeros of -2x^2-7x-5=0 are x=-5/2 ,x=-1