What are the solutions to the equation x^2+x-3=0 ?

The solutions to the equation x^2+x-3=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

Find the zeros of x^2+x-3=0

The zeros of x^2+x-3=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2

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x^{2} + x - 3 = 0

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Decimal Notation

x = 1.30277 \dots, x = - 2.30277 \dots

Solution steps

x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 3) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 1}, x_{2} = \frac{- 1 - 13}{2 \cdot 1}

x = \frac{- 1 + 13}{2 \cdot 1} : \frac{- 1 + 13}{2}

x = \frac{- 1 - 13}{2 \cdot 1} : \frac{- 1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

4 x^{2} - 20 x + 9

5 \cdot 4 \cdot 3

\frac{( - 0.999999 - ( - 1 ) )}{- 0.01 - 0}

0.01 x^{2} + 0.06 x - 0.05 = 0

2 x^{3} + 9 x^{2} + 13 x + 6

What are the solutions to the equation x^2+x-3=0 ?
The solutions to the equation x^2+x-3=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2
Find the zeros of x^2+x-3=0
The zeros of x^2+x-3=0 are x=(-1+sqrt(13))/2 ,x=(-1-sqrt(13))/2