What is 1/(x+2)> 3/(x+1) ?

The solution to 1/(x+2)> 3/(x+1) is x<-5/2 \lor-2<x<-1

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1/(x+2)> 3/(x+1)

\frac{1}{x + 2} > \frac{3}{x + 1}

x < - \frac{5}{2} or - 2 < x < - 1

Interval Notation

(- \infty, - \frac{5}{2}) \cup (- 2, - 1)

Decimal Notation

x < - 2.5 or - 2 < x < - 1

Solution steps

\frac{1}{x + 2} > \frac{3}{x + 1}

Rewrite in standard form

\frac{- 2 x - 5}{( x + 2 ) ( x + 1 )} > 0

Identify the intervals

x < - \frac{5}{2} or - 2 < x < - 1

\frac{3}{9} \cdot \frac{2}{8} \cdot \frac{1}{7}

3 x^{2} - 9 x - 54 > 0

- 5 x - 3 \geq - x + 9

- x^{2} + 3 x + 5 = 0

∣ 4 - 5 x ∣ + 5 \geq 8

What is 1/(x+2)> 3/(x+1) ?
The solution to 1/(x+2)> 3/(x+1) is x<-5/2 \lor-2<x<-1