What is factor 27t^3-125q^3 ?

The solution to factor 27t^3-125q^3 is (3t-5q)(9t^2+15tq+25q^2)

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factor 27t^3-125q^3

factor

27 t^{3} - 125 q^{3}

(3 t - 5 q) (9 t^{2} + 15 tq + 25 q^{2})

Solution steps

27 t^{3} - 125 q^{3}

Apply exponent rules

= (3 t)^{3} - (5 q)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(3 t)^{3} - (5 q)^{3} = (3 t - 5 q) ((3 t)^{2} + 3 t \cdot 5 q + (5 q)^{2})

= (3 t - 5 q) ((3 t)^{2} + 3 t \cdot 5 q + (5 q)^{2})

Simplify

(3 t)^{2} + 3 t \cdot 5 q + (5 q)^{2} : 9 t^{2} + 15 tq + 25 q^{2}

= (3 t - 5 q) (9 t^{2} + 15 tq + 25 q^{2})

\frac{h}{- 4} = 21

(\frac{5}{3})^{5}

(1 + 72) (5 + 2)

\frac{2 ( x + 5 )}{4} = 5 x - 2

5 (2 x - 1) = 4 (3 x - 2)

What is factor 27t^3-125q^3 ?
The solution to factor 27t^3-125q^3 is (3t-5q)(9t^2+15tq+25q^2)