What are the solutions to the equation x^2+8x-8=0 ?

The solutions to the equation x^2+8x-8=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))

Find the zeros of x^2+8x-8=0

The zeros of x^2+8x-8=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))

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x^{2} + 8 x - 8 = 0

x = 2 (6 - 2), x = - 2 (2 + 6)

Decimal Notation

x = 0.89897 \dots, x = - 8.89897 \dots

Solution steps

x^{2} + 8 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 8) = 46

x_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 6}{2 \cdot 1}

x = \frac{- 8 + 4 6}{2 \cdot 1} : 2 (6 - 2)

x = \frac{- 8 - 4 6}{2 \cdot 1} : - 2 (2 + 6)

The solutions to the quadratic equation are:

x = 2 (6 - 2), x = - 2 (2 + 6)

(3 k - 2)^{2} = 100

\frac{\frac{5}{( x + h )} + ( \frac{5}{x} )}{h}

- 4 (- 10 + 1)

5 a - 15

What are the solutions to the equation x^2+8x-8=0 ?
The solutions to the equation x^2+8x-8=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))
Find the zeros of x^2+8x-8=0
The zeros of x^2+8x-8=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))